Common Mistakes with call, apply, and bind
Mistakes candidates make with call, apply, and bind in interviews.
Common Mistakes with call, apply, and bind
Mistake 1: Confusing call and apply Arguments
call takes comma-separated args. apply takes an array. Mixing them up is common.
Mistake 2: Expecting bind to Invoke
bind returns a function. You must call it separately. fn.bind(obj) does nothing until you call the result.
Mistake 3: Trying to Re-bind
bound.bind(newObj) does not change this. The first bind wins.
Mistake 4: Using bind on Arrow Functions
Arrows ignore bind. this is lexical and cannot be changed.
Mistake 5: Forgetting to Pass this as First Argument
fn.call(5, 10) sets this to 5 (a primitive, boxed to Number) and passes 10 as the first arg. Usually, you want fn.call(obj, 5, 10).
The Takeaway
Mistakes: confusing call (comma) and apply (array) args, expecting bind to invoke (it returns a function), trying to re-bind (first bind wins), using bind on arrows (ignored), and forgetting this as the first argument. Know the differences clearly.
call takes comma-separated arguments: fn.call(obj, arg1, arg2). apply takes an array: fn.apply(obj, [arg1, arg2]). Both invoke immediately with the specified this.
No. bind returns a new function with this bound. You must call it separately. This is the key difference from call and apply, which invoke immediately.
No. The first bind wins. bound.bind(newObj) does not change this. The bound function keeps the original this from the first bind call.
No. Arrow functions inherit this from their lexical scope. bind, call, and apply cannot change an arrow's this. They can still pass arguments, but this stays lexical.
The this value. fn.call(thisArg, arg1, arg2). fn.apply(thisArg, [arg1, arg2]). fn.bind(thisArg, arg1, arg2). If you do not care about this, pass null.
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