The answer
Because integers are primitives. Java passes a copy of the primitive value, so the original variable remains untouched.
Pass by Value vs Pass by Reference Explained
Why doesn't changing an integer inside a Java function change the original?
More FAQs in Pass by Value vs Pass by Reference Explained
Pass by Value means a copy of the variable's data is passed to the function. Modifications inside the function do not affect the original variable.
Pass by Reference means the memory address of the variable is passed. Modifications inside the function will alter the original variable's data.
Java is strictly pass-by-value. However, for objects/arrays, the 'value' passed is the memory reference, which allows the object's contents to be modified.
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