How does the execution flow in a nested loop work?
The outer loop executes once, which triggers the inner loop. The inner loop must complete all of its iterations before the outer loop can advance to its next step.
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More FAQs in The Inner Loop vs The Outer Loop Execution Flow
Yes, variables declared in the outer loop (like the 'i' counter) are perfectly visible and accessible inside the inner loop.
No. Any variables declared inside the inner loop are destroyed as soon as the inner loop finishes, making them invisible to the outer loop.
In modern languages, redefining the same variable (like 'int i') in the inner loop causes a compilation error. If you mutate the outer 'i' instead, you break the loop logic.
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