The answer
Math.max.apply(null, [1, 2, 3]) returns 3. In modern JS, use spread: Math.max(...[1, 2, 3]). Both work, but spread is more readable.
Practical Use Cases for call, apply, and bind
How do you find the max value in an array using apply?
More FAQs in Practical Use Cases for call, apply, and bind
Use call: Array.prototype.slice.call(arguments) borrows slice to convert array-like objects to arrays. Array.prototype.forEach.call(nodeList, fn) borrows forEach for NodeLists.
Use bind: setTimeout(obj.method.bind(obj), 1000). Or use an arrow wrapper: setTimeout(() => obj.method(), 1000). bind permanently sets this for the returned function.
In the child constructor, call the parent constructor with this: Person.call(this, name). This borrows the parent constructor and sets properties on the child instance.
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