The answer
No, traversing from N to 1 takes the exact same amount of hardware cycles as traversing from 1 to N.
No, traversing from N to 1 takes the exact same amount of hardware cycles as traversing from 1 to N.
If the outer loop runs from 1 to N, the number of stars per row is N - row + 1.
Reversing the outer loop (starting from N and decrementing) is usually much cleaner and easier to read, reducing the chance of off-by-one math errors.
Use the same loop structure, but inside the inner loop, print the variable 'col' (for 1234, 123) or 'row' (for 4444, 333).
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