Does an async function always return a promise in JavaScript?
Yes. If you return a value, it is wrapped in Promise.resolve. If you throw, it becomes Promise.reject. If you return a promise, it is returned as-is.
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More FAQs in async/await in JavaScript: A Complete Guide
Syntactic sugar over promises. async functions always return a promise. await pauses the function until a promise settles, then returns the fulfilled value or throws the rejection reason. It makes async code look synchronous.
Use try/catch around the await calls. If any await rejects, the catch block runs with the rejection reason. try/catch also catches thrown errors inside the try block.
Use Promise.all: const [a, b] = await Promise.all([fetchA(), fetchB()]). Start all promises at once, then await all. This is much faster than sequential await for independent operations.
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